Taylor expansion for f(x,y) about (x0,y0) ?

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SUMMARY

The discussion focuses on the Taylor expansion for a function f(x,y) around the point (x0,y0). The initial step involves expanding f in terms of x around x0, leading to the expression f(x0 + hx, y0 + hy) = f(x0, y0 + hy) + hx ∂xf(x0, y0 + hy) + hx² ∂²xf(x0, y0 + hy) + ... The user seeks clarification on the derivation of the hx² term, indicating a foundational understanding of the 1D Taylor expansion. The conversation emphasizes the step-by-step approach to applying the Taylor expansion in multiple dimensions.

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izzy93
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Can someone please explain the Taylor expansion for f(x,y) about (x0,y0) ?

Would really appreciate some sort of step by step answer :)

thankyou
 
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Simple, just take a Taylor expansion in x around x_{0}
<br /> f(x_{0}+h_{x},y_{0}+h_{y})=f(x_{0},y_{0}+h_{y})+h_{x} \partial_{x}f(x_{0},y_{0}+h_{y})+h_{x}^{2}\partial_{x}^{2}f(x_{0},y_{0}+h_{y})+\cdots<br />
Then take the Tavlor expansion in y of each term. Simple but tedious.
 
Last edited:
Thanks for the reply, it looks logical but I'm stuck on how it all comes together/
and where does the h^2(x) term in the 3rd term on the right come from
 
I am applying the 1D Taylor expansion to the x-variable. I am assuming, you know about the 1D Taylor expansion right?
 
yes I do using this equation, f(x) = f(x0) + f '(x0)/1! (x-x0) ...
 
The notation I am using:
<br /> h_{x}=x-x_{0}<br />
 
ok, I think i get it, bit slow atm! thankyou!
 

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