1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Taylor Series question

  1. Mar 29, 2009 #1
    1. The problem statement, all variables and given/known data
    Determine the Taylor Series for f(x) = ln(1-3x) about x = 0


    2. Relevant equations

    ln(1+x) = [tex]\sum\fract(-1)^n^+^1 x^n /{n}[/tex]


    3. The attempt at a solution

    ln(1-3x) = ln(1+(-3x))

    ln(1+(-3x)) = [tex]\sum\fract(-1)^n^+^2 x^3^n /{n}[/tex]

    Is that right?
     
  2. jcsd
  3. Mar 29, 2009 #2
    The -1 is in the right place, but I'm not sure why the 3 migrated to the exponent.
     
  4. Mar 29, 2009 #3
    So is it:
    [tex]
    \sum\fract(-1)^n^+^2 3x^n /{n}
    [/tex]
     
  5. Mar 29, 2009 #4
    You check it yourself by computing the first couple of terms in the Taylor series.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Taylor Series question
  1. Taylor Series Questions (Replies: 23)

  2. Taylor series question (Replies: 17)

  3. Taylor series question (Replies: 3)

Loading...