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Taylor Series question

1. Homework Statement
Determine the Taylor Series for f(x) = ln(1-3x) about x = 0


2. Homework Equations

ln(1+x) = [tex]\sum\fract(-1)^n^+^1 x^n /{n}[/tex]


3. The Attempt at a Solution

ln(1-3x) = ln(1+(-3x))

ln(1+(-3x)) = [tex]\sum\fract(-1)^n^+^2 x^3^n /{n}[/tex]

Is that right?
 
The -1 is in the right place, but I'm not sure why the 3 migrated to the exponent.
 
So is it:
[tex]
\sum\fract(-1)^n^+^2 3x^n /{n}
[/tex]
 
1,356
0
You check it yourself by computing the first couple of terms in the Taylor series.
 

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