# Taylor Series question

1. Mar 29, 2009

### ganondorf29

1. The problem statement, all variables and given/known data
Determine the Taylor Series for f(x) = ln(1-3x) about x = 0

2. Relevant equations

ln(1+x) = $$\sum\fract(-1)^n^+^1 x^n /{n}$$

3. The attempt at a solution

ln(1-3x) = ln(1+(-3x))

ln(1+(-3x)) = $$\sum\fract(-1)^n^+^2 x^3^n /{n}$$

Is that right?

2. Mar 29, 2009

### Wretchosoft

The -1 is in the right place, but I'm not sure why the 3 migrated to the exponent.

3. Mar 29, 2009

### ganondorf29

So is it:
$$\sum\fract(-1)^n^+^2 3x^n /{n}$$

4. Mar 29, 2009

### e(ho0n3

You check it yourself by computing the first couple of terms in the Taylor series.