Temp and Pressure measure of KE(average)

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Temperature and pressure in gases are related to the average translational kinetic energy (KE) of molecules, as per kinetic molecular theory. In an isothermal process, while temperature remains constant, the gas expands, which decreases its density and allows pressure to change. The pressure of a gas is influenced not only by average KE but also by the number density of the gas molecules. Therefore, it is possible to maintain constant temperature while pressure varies due to changes in density during expansion. Understanding this relationship clarifies the confusion regarding simultaneous changes in temperature and pressure.
Zahid Iftikhar
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Hi
My question is related to interpretation of temperature and pressure in gases on the basis of kinetic molecular theory.
According to it, both temperature and pressure are proportional to average translational kinetic energy of the gas molecules.
Now in a situation where an ideal gas in confined in a cylinder and is heated and it is an isothermal process i.e the temperature is kept constant. How is it possible to increase the pressure according to above stated rule. Now if temperature is constant, average KE should be constant which also determines the pressure. Where I am confused is , if average KE is constant, both temperature and pressure should be simultaneously constant. One of them can't be kept constant while the other changes.
Please help.
Regards
Zahid
 
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Zahid Iftikhar said:
Hi
My question is related to interpretation of temperature and pressure in gases on the basis of kinetic molecular theory.
According to it, both temperature and pressure are proportional to average translational kinetic energy of the gas molecules.
Now in a situation where an ideal gas in confined in a cylinder and is heated and it is an isothermal process i.e the temperature is kept constant. How is it possible to increase the pressure according to above stated rule. Now if temperature is constant, average KE should be constant which also determines the pressure. Where I am confused is , if average KE is constant, both temperature and pressure should be simultaneously constant. One of them can't be kept constant while the other changes.
Please help.
Regards
Zahid
The process you are describing does not exist or rather is overconstrained. Isothermal heating is accompanied by expansion:
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/isoth.html
 
It's difficult to heat something while keeping the temperature constant ...
[edit] ah .. too late.
 
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russ_watters said:
The process you are describing does not exist or rather is overconstrained. Isothermal heating is accompanied by expansion:
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/isoth.html
russ_watters said:
The process you are describing does not exist or rather is overconstrained. Isothermal heating is accompanied by expansion:
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/isoth.html
Yes it is isothermal expansion process. The cylinder I mentioned is fitted with frictionless piston and it moves up with more heat added to the working substance and hence does work. My question relates to keeping temperature constant and increasing the pressure. As average KE determines both the temperature and the pressure, how is it possible to change one and fix other.
High regards for your reply.
Zahid
 
Zahid Iftikhar said:
The cylinder I mentioned is fitted with frictionless piston
Nice to know... :rolleyes: And @russ_watters' link says it all: Q=W
 
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The pressure depends on the average KE but not only on it. If you look up the actual formula, it depends on the density of the gas too (number density, n, for example). So as the gas expands n decreases and so does the pressure. At unchanged average KE per molecule.
 
nasu said:
The pressure depends on the average KE but not only on it. If you look up the actual formula, it depends on the density of the gas too (number density, n, for example). So as the gas expands n decreases and so does the pressure. At unchanged average KE per molecule.[/QUOTE
Yes, that is the point I am missing. The density does play a role in it as it does not remain constant.
Thanks.
 
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