Temperature Problem of steel rod

Click For Summary
SUMMARY

The discussion revolves around calculating the change in temperature required to elongate a steel rod by the same amount as a 500 N force. Key parameters include Young's modulus (20 x 1010 Pa), shear modulus (8.4 x 1010 Pa), and the average linear expansion coefficient (11 x 10-6 °C-1). The solution involves applying Hooke's Law to find the displacement due to the force and equating it to the linear expansion equation to solve for the temperature change. The user successfully resolved the problem using the formula: F/A = Y * coefficient of linear expansion * change in temperature.

PREREQUISITES
  • Understanding of Hooke's Law and its application in uniaxial stress.
  • Knowledge of Young's modulus and its significance in material deformation.
  • Familiarity with the concept of linear thermal expansion and its coefficient.
  • Basic algebra skills for solving equations involving force, area, and temperature change.
NEXT STEPS
  • Learn how to apply Hooke's Law in various material stress scenarios.
  • Study the derivation and applications of Young's modulus in engineering contexts.
  • Explore the principles of thermal expansion in different materials beyond steel.
  • Investigate the relationship between stress, strain, and temperature in materials science.
USEFUL FOR

Students and professionals in physics, mechanical engineering, and materials science who are dealing with thermal expansion and material deformation calculations.

atelaphobia
Messages
7
Reaction score
0
Thermal Expansion Problem

i posted this thread in another forum because i really don't know where this question would apply but here goes
i've been working on this problem forever and i don't know what I'm doing wrong!
a steel rod undergoes a stretching force of 500 N. Its cross sectional area is 2.00 cm^2. Find the change in temperature that would elongate the rod by the same amount as the 500-N force does.
here's some info that may be of some use but i don't know how to use it!
average linear expansion coefficient: 11x10^(-6)
young's modulus: 20x10^10
shear modulus: 8.4x10^10
thanks in advance you guys!
 
Last edited:
Physics news on Phys.org
Well assuming the material is elastic linear, you can apply Hooke's Law for uniaxial stress and find the displacement, then with the displacement found, you could equal it with the linear expansion equation for heat, and solve for the temperature difference (change in temperature). Btw, wrong forum, this is introductory physics.
 
atelaphobia said:
i posted this thread in another forum because i really don't know where this question would apply but here goes
i've been working on this problem forever and i don't know what I'm doing wrong!
a steel rod undergoes a stretching force of 500 N. Its cross sectional area is 2.00 cm^2. Find the change in temperature that would elongate the rod by the same amount as the 500-N force does.
here's some info that may be of some use but i don't know how to use it!
average linear expansion coefficient: 11x10^(-6)
young's modulus: 20x10^10
shear modulus: 8.4x10^10
thanks in advance you guys!

"Young's modulus" measures how much a solid stretches in response to a force (basically the Hook's law coefficient).
"Shear modulus" measures how much the cross section of a solid contracts in response to a stretching of the length.
"Linear expansion coefficient" measures how much a solid will expand (in length) in response to a temperature change.

No, I didn't happen to know that off hand. I looked them up, right now, on "google.com".

Use Young's modulus to determine how much the material will stretch in response to a 500 N force. Use the linear expansion coefficient to determine the temperature necessary to produce that expansion.
 
Cyclovenom said:
Btw, wrong forum, this is introductory physics.

like i said.. i didnt know where to put this question... i saw clac and beyond and figured it would be a good place to put it...so my apologies..

i figured out the problem last night right after i posted it!

F/A=Y*coefficient of linear expansion*change in temp and solved for temp

thanks you guys!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
20K