Tension and Velocity: Physics Explained

AI Thread Summary
Tension in a string with a weight is equal to the mass times gravity, but when the string gains velocity and moves horizontally, the tension increases significantly, potentially leading to the string snapping. The opposing forces due to the object's velocity create additional tension, influenced by centripetal acceleration. Real-world tests are suggested to observe these effects, though some participants lack the necessary materials for experimentation. The discussion highlights the relationship between tension, velocity, and the resulting forces acting on the string. Understanding these dynamics is crucial for predicting the string's behavior under different conditions.
TimeInquirer
Messages
32
Reaction score
0
Hello, I was recently reading a physics book and was told that, if a string were to hang down with a weight attached to it, its tension would be the mass times gravity. However, if it were to gain some velocity and move from left to right, the tension would increase enough so that the string would be cut. The book doesn't go into further detail. Does the force of the velocity oppose the string? Can someone please explain this to me, possibility showing equations to describe this motion? Thanks
 
Physics news on Phys.org
The string will most likely snap. How come you do not do a real world test?
 
I have watched a few videos, and I lack the sufficient material to produce adequate results (a.k.a poor strings and lack of a weight). I understand that it does happen but not sure why.
 
What is the path of the object when it is swinging? What do you know about centripetal acceleration?
 
It's all about the force going into the string and force going out towards the book.
That will result a friction and centripetal acceleration that makes the string snap. ;)
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top