(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Tension- Hanging Sign

A 20.0 kg sign is being held up by 2 ropes. Each rope makes a 60 degree angle with the sign. So there is an upright triangle, each angle 60 degrees. I have to calculate the tenstion in the two ropes.

So far, I have

[tex]\Sigma[/tex] F[tex]_{}y[/tex]=ma[tex]_{}y[/tex]

+Fa[tex]_{}1[/tex]sin60 + Fa[tex]_{}2[/tex]sin60 = 20 kg (9.81 m/s[tex]^{}2[/tex])

I divided by sin60

Fa[tex]_{}1[/tex] + Fa[tex]_{}2[/tex] = 226.55 N

Each rope has 112.78 N

I'm not sure if i have to do the sum of the forces in the x direction or if the work i already did is correct.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Tension- Hanging Sign

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