a mass of 0.5kg is suspended from a flywheel. if the mass is released from rest and falls a distance of 0.5m in 1.5s, calculate : The tension in the rope. acceleration is 0.444ms-2.
t-w = -ma
The Attempt at a Solution
t = m(ag)
t = 0.5(0.4444=9.81)
t = 5.127n
w = mg = 0.5x9.81 4.9n
so t-w 0.227n is rope tension.
Check by inserting numbers into equation of t-w = -ma
so: 5.127 - 4.905 = 0.5 x 0.222.
The last equation doesn`t marry up?