CINA
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Homework Statement
3. A flying chicken (m = 450[gram]) lands in the middle of a taught laundry wire of length l=10[m]. The wire has a negligible mass. The chicken causes the wire to stretch by 0.05% from its original length. Find the tension in each segment of the wire.
http://img517.imageshack.us/img517/2922/asdfgggea7.th.jpg http://g.imageshack.us/thpix.php
Homework Equations
Fext = 0
X) Ft1x - Ft2x = 0
Y) Ft1y + Ft2y - Fg = 0
The Attempt at a Solution
Since the length increases by .05% you can make a triangle with lengths 10m ( the origianl length), 5.25m and 5.25m (half of the new length with the chicken in the middle). you can split this into two right triangles with sides 5-5.25-x (doesn't matter right?). Using arccos (5/5.25) you get 17.8 degrees.
Fty1 & Fty2 = Ftx tan 17.8
getting 2 Ftx tan 17.8 = Fg
Ftx = 6.87 N
Ft = Ftx/Cos 17.8 = 7.2 N
The Problem
Students in my class got 69.8 N, and after looking up tension I found that it increases as things stretch. Our teacher never said anything about this (but gave a problem on it). How does the streching of the string play into this? Is there some equation I'm not putting to use?
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