Tension in string - hanging block

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Homework Help Overview

The discussion revolves around calculating the tension in a string supporting a hanging block. Participants are comparing their calculations with a solution manual, which presents a different value for the tension.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the components of tension in the strings, specifically how the y-component of tension relates to the weight of the block and how the x-component relates to the tension in another string. There is an emphasis on clarifying the calculations and ensuring the correct interpretation of angles and units.

Discussion Status

There is an ongoing exploration of the calculations involved in determining the tension. Some participants express uncertainty about the steps taken and suggest a more detailed breakdown of the equations. The original poster and others are questioning the correctness of the solution manual's answer.

Contextual Notes

Participants are working under the assumption that the solution manual's answer may be incorrect, as they arrive at a different value for the tension. There is also a note about the importance of correctly interpreting angles in the context of the problem.

tony873004
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Homework Statement


Find the tension in string 1
hangingmass.GIF

I don't get the same answer as the solution manual.

My attempt:
The y-component of string 2’s tension must equal the weight of the block.
The x-component of string 2’s tension must equal the tension of string 1.
T1=T2x=T2y/tanθ =23°

solution manual says 34 N.

 
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tony873004 said:
My attempt:
The y-component of string 2’s tension must equal the weight of the block.
The x-component of string 2’s tension must equal the tension of string 1.
Good.
T1=T2x=T2y/tanθ =23°
Not sure what you did here (better to write the equations step by step), but I think you found that the tension in string 1 is about 23 N (not degrees!). Sounds right to me.

solution manual says 34 N.
I'd say that was wrong.
 
Doc Al said:
...Not sure what you did here (better to write the equations step by step).

tanθ=opposite/adjacent
tanθ=T2y/T2x
tanθ=mg/T2x
T2x=T1=mg/tanθ = 23 N (oops,not degrees!)

Thanks Doc Al! Just wanted to make sure I wasn't crazy!
 
tony873004 said:
tanθ=opposite/adjacent
tanθ=T2y/T2x
tanθ=mg/T2x
T2x=T1=mg/tanθ = 23 N (oops,not degrees!)
Much better.

Thanks Doc Al! Just wanted to make sure I wasn't crazy!
You are welcome.
 

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