- #1
sisigsarap
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I am having a little difficulty with a physics problem, hopefully someone can help!
Q. The distance between two telephone poles is 50.0m. When a 1.00kg bird lands on the telephone wire midway between the poles, the wire sags .200m. Ignore the weight of the wire.
Using the data given I used 25.0m and .200m as legs of a right triangle and solved for the hypotenuse which I found to be 25.0007999. Then I found the angles that made up that triangle.
Then I did the sum of Force x = T1 sin89.54 + T2sign89.54 = 0
and the sum of Force y = -T1cos89.54 + -T2cos89.54 = 9.8
Then solving for T2 I get approximately 610 N as well as 610 N for T1. So a net Force Y of -9.8.
What am i doing wrong? I know the answer is 613 N, but I am lost.
Thanks!
Q. The distance between two telephone poles is 50.0m. When a 1.00kg bird lands on the telephone wire midway between the poles, the wire sags .200m. Ignore the weight of the wire.
Using the data given I used 25.0m and .200m as legs of a right triangle and solved for the hypotenuse which I found to be 25.0007999. Then I found the angles that made up that triangle.
Then I did the sum of Force x = T1 sin89.54 + T2sign89.54 = 0
and the sum of Force y = -T1cos89.54 + -T2cos89.54 = 9.8
Then solving for T2 I get approximately 610 N as well as 610 N for T1. So a net Force Y of -9.8.
What am i doing wrong? I know the answer is 613 N, but I am lost.
Thanks!