- #1
nicolette2413
- 8
- 0
1. A 100N light is suspended from a beam with two wires. Both wires make angles of 40 degrees with the beam.
2. What is the tension in the wires?
3. Ok here's what I have so far...
Sum Fx: T2(cos 40)-T1(cos 40)=0
so T2=T1
Sum Fy: T2 (sin 40)+T1(sin 40+(-100)=0
so T2(sin 40)+T1(sin 40)=100
With subsitutions...
T1(sin 40)+T1(sin 40)=100
And T1=77.8N, T2=77.8N, and T3=100N
Is this correct? And does changing the angle change the final breakdown? Such as if the angle was 30 degrees vice 40 degrees??
2. What is the tension in the wires?
3. Ok here's what I have so far...
Sum Fx: T2(cos 40)-T1(cos 40)=0
so T2=T1
Sum Fy: T2 (sin 40)+T1(sin 40+(-100)=0
so T2(sin 40)+T1(sin 40)=100
With subsitutions...
T1(sin 40)+T1(sin 40)=100
And T1=77.8N, T2=77.8N, and T3=100N
Is this correct? And does changing the angle change the final breakdown? Such as if the angle was 30 degrees vice 40 degrees??