Tension pulls the bucket upward

  • Thread starter Thread starter 21ducks
  • Start date Start date
  • Tags Tags
    Tension
AI Thread Summary
The discussion focuses on calculating the acceleration of a 3.0 kg bucket being lowered into a well, with a tension of 9.8 N in the rope. The correct approach involves using the formula Net Force (F) divided by mass (m) to find acceleration (a). The weight of the bucket is calculated as 29.43 N (3.0 kg multiplied by 9.81 m/s²), and when the tension is subtracted, it results in a net force of 19.63 N. This net force is then used to determine the acceleration, confirming the calculations and understanding of the physics involved. The participants clarify the steps to ensure accurate comprehension of the concepts.
21ducks
Messages
11
Reaction score
0
I have been trying to figure out how this works. I know what the answer is since someone else has previously posted the answer in the forums. I want to learn how to do it though. Here is the question:

A 3.0 kg bucket is being lowered by a rope into a 10 m deep well, starting from the top. The tension in the rope is 9.8 N. The acceleration of the bucket will be:

6.5 m/s/s downward.

He used the following formula Net F / m = a which is 19.66 / 3.0 kg = 6.5 m/s/s.

How did he get the 19.66??
 
Physics news on Phys.org
draw a FBD of the bucket.
tension pulls the bucket upward and w=mg pulls it downward.
if you sum the force in either direction, you should get that.

i've used 9.81 as the gravity and i got 19.63 as force instead of 19.66 but it should be fine.
 
From the weight of the bucket (3.0kg * 9.81m/s/s) less the tension (9.8N) = 19.66
 
Thanks! So let me see if I understand now. Do I multiply 3.0 X 9.81 = 29.43 for weight and then subtract the tension to get 29.43 - 9.8 = 19.63. Then plug the 19.63 into the Net F/ m = a ?
 
Perfect! Thank you!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top