The ambiguous question came to my last week exam

[abrowaqas]

Homework Statement

If f(x) = x^3,
show that
f(a,b,c) = a+b+c

Homework Equations

I have given exam last week. and i am still searching for this question .. what this is about. is it from Tensor coordinate transformation or some numerical analysis involve here.

kindly somebody please help to solve or give idea to this question.

The Attempt at a Solution

 

[Mark44]

Homework Statement

If f(x) = x^3,
show that
f(a,b,c) = a+b+c

Homework Equations

I have given exam last week. and i am still searching for this question .. what this is about. is it from Tensor coordinate transformation or some numerical analysis involve here.

kindly somebody please help to solve or give idea to this question.

The Attempt at a Solution

As stated here, the question doesn't make sense. Your function f takes a single argument, so you could evaluate f(a), or f(b), or f(c), but not f(a, b, c).

 

[abrowaqas]

But this question came in final Exam ... It has no error as paper setter claimed ..

How it will be solved ?
Anybody kindly help to solve this question

 

[Office_Shredder]

If this is the full problem statement as given, it has no solution because it doesn't make any sense. What is the definition of f(a,b,c) supposed to be?

 

[tazzzdo]

Here you go:

Given a function f:ℝ → ℝ

f(x) := x³

f(a, b, c) := a + b + c

where x, a, b, c \in ℝ

QED by trivialization.

lol now it's formal

 

[abrowaqas]

I think all members are not taking this question seriously..

well this question appeared in Pakistan's superior examination for recruitment in March 2012.

this is the link of that paper..

http://www.cssforum.com.pk/css-past-papers/css-2012-past-papers/61352-someone-please-load-app-maths-paper.html

it is Paper II and question No. 8(a)..

kindly check ..
and then put funny remarks.

 

[HallsofIvy]

It's hard to be serious about non-sense. And it is still non-sense. However you define "f(x)" that gives you NO information about "f(a, b, c)". They can't be the same function.