The body slides off an inclined plane

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SUMMARY

The discussion centers on the physics of an object sliding off an inclined plane, specifically using the equation of motion. The user derived the acceleration (a) as a function of gravitational force (g), angle of inclination (α), and friction coefficient (f). The calculations confirm that with a friction coefficient of 0.26, the object experiences a specific acceleration and velocity over time. The solution appears to be correct based on the provided equations and values.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with trigonometric functions in physics
  • Knowledge of friction coefficients and their impact on motion
  • Basic algebra for solving equations
NEXT STEPS
  • Study the effects of varying friction coefficients on inclined plane motion
  • Learn about the role of angle of inclination in determining acceleration
  • Explore advanced topics in dynamics, such as rotational motion on inclined planes
  • Investigate real-world applications of inclined plane physics in engineering
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Students of physics, educators teaching mechanics, and engineers involved in motion analysis will benefit from this discussion.

Adeopapposaurus
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Homework Statement
The body slides off an inclined plane with an inclination angle of α = 60°. After t = 2s, the body speed is v = 14.7 m/s. Find the friction coefficient f. The initial velocity of the body is 0 m/s and the gravity acceleration g = 10 m/s^2 .
Relevant Equations
F = f * N
F = fmg*cos(α)
ma = mg * sinα - fmg * cosα
ma = mg * sinα - fmg * cosα
a = g (sinα-f * cosα)
v = g*t(sinα - f * cosα)
14.7 = 10 * 2 (sin60 - f * cos60)
f = 0.26

Can someone please check if my solution is correct? I'd really appreciate that.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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