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Therefore as a consequence.... the longer the carrier of an EMF, the more definite/indefinite parts or Quantum Mechanics of “Atoms” the Emf must overcome and endure to pass current equally through the Circuit, Thus Increasing the Total Resistance in respect to the Emf.

The Carrier will be expressed as the Conductor Wire and the Conductor Load, because it carries the Emf.

For Example: r1+r2+r3+r4+r5+r6+r7+r8+r9......ect; Consider these Atoms throughout the Entire length of Conductor Wire to the SMALLEST degree. This is the basic Resistance of each atom to an Emf that must transfer electrons through it.

And R10+R11+R12+R13+R14+R15+R16+R17+R18......ect. Consider these also Atoms throughout the Entire length of the Conductor Load to the SMALLEST degree. This is the basic Resistance of each atom to an Emf that must transfer electrons through it.

Copper Atoms: Which is expressed above as Lowercase r's. (The Conductor Wire)

Aluminum Atoms: Which is expressed above as Uppercase R's. (The Conductor Load)

First Imagine a strand of Conductive Copper Wire consisting of Single Copper atoms, followed by a strand of Conductive Load. (r1+r2+r3+r4+r5+r6+r7+r8+r9+R10+R11+R12+R13+R14+R1 5+R16+R17+R18)

Now induce an Emf that is suposedly insufficient to work the Load.

Before I can move on I need to ask these questions…………….

1. A. What happens as a result of insufficient EMF?

B. Does the charge die along the way? If so WHY? HOW?

2. A. Does the insufficient Emf induce current on ANY electrons or only SOME?

B. If some do they squash against the ones that can’t move???

C. Is there momentarily Current only until the electrons come to a hault?