The Change in Elastic Potential Energy with Different Spring Stretches

AI Thread Summary
The discussion revolves around calculating the change in elastic potential energy for a spring with a constant of 3200 N/m, initially stretched to 1.44 J. The calculations for different stretches and compressions reveal discrepancies, particularly in the results for compressions. The correct change in potential energy for a 2.0 cm compression is -2.08 J, while for a 4.0 cm compression, it should be -4 J, not 1.1 J as initially stated. Participants emphasize the importance of correctly applying the formula for potential energy, noting that potential energy remains positive regardless of compression due to the squaring of displacement. Accurate calculations are crucial for understanding the behavior of springs under different conditions.
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Homework Statement


A spring constant of ##3200 N/m## is initially streched until the elastic potential energy is ##1.44## J (##U=0## for no stretch). What is the change in elastic potential energy if the initial stretch is changed to (a) a stretch of ##2.0## cm, (b) a compression of ##2.0## cm, (c) a compression of ##4.0## cm.

Homework Equations


##\Delta U=U_f-U_i##
##U=\frac{1}{2}kx^2##

The Attempt at a Solution



(a) ##\Delta U=U_f-U_i=\frac{1}{2}(3200)(0.02)^2-1.44=-0.8 J##

(b) ##\Delta U=U_f-U_i=-\frac{1}{2}(3200)(0.02)^2-1.44=-2.08 J##

(c) ##\Delta U=U_f-U_i=-\frac{1}{2}(3200)(0.04)^2-1.44=-4J##

The first answer (a) is correct but the last 2 they get (b) ##-0.8J## and (c) ##1.1J## respectively. How?
 
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lion_ said:

Homework Statement


A spring constant of ##3200 N/m## is initially streched until the elastic potential energy is ##1.44## J (##U=0## for no stretch). What is the change in elastic potential energy if the initial stretch is changed to (a) a stretch of ##2.0## cm, (b) a compression of ##2.0## cm, (c) a compression of ##4.0## cm.


Homework Equations


##\Delta U=U_f-U_i##
##U=\frac{1}{2}kx^2##

The Attempt at a Solution



(a) ##\Delta U=U_f-U_i=\frac{1}{2}(3200)(0.02)^2-1.44=-0.8 J##

(b) ##\Delta U=U_f-U_i=-\frac{1}{2}(3200)(0.02)^2-1.44=-2.08 J##

(c) ##\Delta U=U_f-U_i=-\frac{1}{2}(3200)(0.04)^2-1.44=-4J##

The first answer (a) is correct but the last 2 they get (b) ##-0.8J## and (c) ##1.1J## respectively. How?
You should check your math...
 
PhanthomJay said:
You should check your math...
If the spring is compressed, isn't potential energy for the spring negative?
 
square a negative and you get a ?
 
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