The conjugate of a Wave-Function

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SUMMARY

The discussion centers on the conjugate of a wave function, specifically for a particle in a box represented by the wave equation \(\psi(x) = A \sin\left(\frac{n \pi x}{L}\right)\). The amplitude \(A\) is defined as \(A = \sqrt{\frac{2}{L}}\), where \(L\) is the length of the box. It is established that the Hermitian conjugate of a real-valued function, such as this wave function, is the function itself, confirming that the wave function is indeed its own conjugate.

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RCulling
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I'm trying to show that the amplitude (A) of the wavefunction for a particle in a box is:

A = sqrt(2/L) : L is the length of the box.

I'm using \psi(x) = Asin ((n*pi*x) / L) as the wave equation.

To do this I'm trying to integrate the probability density function from 0 through to L with respect to x.
But to find the probability density function I need to find the conjugate of the wave function. Which I don't know how to do.
Since there is no i (its a real valued function) does that mean it is its' own conjugate?

I really have no idea and can't seem to find anything on the net.

Thanks :)
 
Last edited:
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The Hermitian conjugate of a real-valued function (square-integrable) is generally the function itself.
 
Ok thanks a lot :)
 

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