Ingvar Astrand
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David said:“Thus for the largest known redshift of z=6.3, the recession velocity is not 6.3*c = 1,890,000 km/sec. It is also not the 285,254 km/sec given by the special relativistic Doppler formula 1+z = sqrt((1+v/c)/(1-v/c)). The actual recession velocity for this object depends on the cosmological parameters, but for an OmegaM=0.3 vacuum-dominated flat model the velocity is 585,611 km/sec. This is faster than light.”
To David (I like your energy) and other interested.
Redshift is not a recession velocity question. The kinematic mechanism behind is the entropy-effect that Clausius coined for the notion he invented when he searched the cause and reason to why heat-radiation moved to equilibrium.
Planck and his colleagues found the cause and reason but didn’t understand how to interpret the constant fractional increasing change between the electrodynamical wave-units. Desperate Planck tried to interpret the value that was measured as differences between wavelengths as continuing change in energy. To do so he inverted the fractional value to the temperature’s change over the frequency spectrum. Wien and Stefan–Boltzmann laws have showed that there is a relation between temperature and wavelengths, but Planck had got lost in his derivation. Einstein later suggested (postulated) that this mathematical artifact “must” be interpreted as quantum-unit.
Planck’s measured value 6.626 x 10^-34 tells us how much an electrodynamical wave is extended from wave to wave or proportional to the distance. This is the simple formula (redshift = constant x distance). So the distance to this 6.3 (6.28) quasar that is redshifted from (1216 to 7636 Angstrom) is: (6.420 x 10^-10 km) / (6.626 x 10^-34) = 9.7 x 10^23 km. The distance defined as light-years -- that is 0.95 x 10^13 km per light-year -- to this 6.28-quasar is near 1000 billion light years.
A quasar’s energy that we receive is proportional to the redshift (energy = z^4). So this 6.28 quasar emits at the wavelength 1216 Angstrom 1555 times more energy than we receive at 7636 Angstrom. This energy drives the light (waves) forward.
When electrodynamic waves increase their lengths their velocities also increase to this simple formula [c + (2c x redshift)^-2]. So the 6.3 quasar’s wavelength of 7636 Angstrom that we receive moves [(2 x 3 x 10^5 x 7.636^-10)^-2] km/s = 0.045 km/s faster than c.
The light-spectrum that we se as stroboscope-frozen moves at the velocity of light, but we can not see that the waves increase their speed with their wave-displacement. But we can understand it when we see the increasing wavelengths between the water-rings from the pebble that is thrown in the water.
Ingvar Astrand, Sweden