The elasticity/stiffness tensor for an isotropic materials

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SUMMARY

The elasticity/stiffness tensor for isotropic and homogeneous materials is defined by two independent material parameters, lambda (λ) and mu (μ), represented mathematically as C_{ijkl} = λδ_{ij}δ_{kl} + μ(δ_{ik}δ_{jl} + δ_{il}δ_{jk}). This formulation is the most general for isotropic materials due to the inherent symmetries that must be satisfied, specifically that μ must equal ν for isotropic materials. In contrast, materials with cubic symmetry require three independent parameters, leading to a different tensor representation. Understanding these distinctions is crucial for applications in material science and engineering.

PREREQUISITES
  • Understanding of elasticity theory
  • Familiarity with tensor notation
  • Knowledge of isotropic and homogeneous materials
  • Basic principles of material symmetry
NEXT STEPS
  • Research the derivation of the elasticity tensor for isotropic materials
  • Study the differences between isotropic and cubic symmetric materials
  • Explore the physical implications of material parameters λ and μ
  • Learn about the application of elasticity tensors in finite element analysis
USEFUL FOR

Material scientists, mechanical engineers, and students studying elasticity and material properties will benefit from this discussion, particularly those interested in the theoretical foundations of material behavior under stress.

Wuberdall
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Hi PF,

As you may know, is the the elasticity/stiffness tensor for isotropic and homogeneous materials characterized by two independent material parameters (λ and μ) and is given by the bellow representation.
C_{ijkl} = \lambda\delta_{ij}\delta_{kl} + \mu(\delta_{ik}\delta_{jl} + \delta_{il}\delta_{jk})
Do any of you know a sound argument, mostly relaying on physical intuition, for why this is the most general form of the elasticity tensor for isotropic and homogeneous materials?

Of course one could always impose all the symmetries (for an isotropic material) upon the elasticity tensor and go through all the necessary and tedious computations to derive this result... But this is unfortunately not what I'm looking for.

And furthermore, what are/is the difference between isotropic materials and materials possessing cubic symmetry, where the most general elasticity tensor instead is written
C_{ijkl} = \lambda\delta_{ij}\delta_{kl} + \mu\delta_{ik}\delta_{jl} + \nu\delta_{il}\delta_{jk}
and is characterized by three (instead of two) independent material parameters.
That is, why is μ = ν for isotopic materials ?

Thanks in advance :-))
 
Physics news on Phys.org
The most general isotropic rank four tensor is of the form with three independent parameters. However, this does not satisfy the symmetries expected from the stiffness tensor. It only does so when ##\mu = \nu##.
 

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