The Exponential Atmosphere: How Pressure and Density Vary with Altitude

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SUMMARY

The discussion centers on deriving the relationship between pressure variation with altitude and the density of air using fundamental physics principles. The participants analyze a horizontal slab of air and establish the differential equation dP/dz = -P(mg)/(kT) by applying the ideal gas law. Key equations and concepts include the balance of forces acting on the slab and the importance of consistent units in calculations. The conversation highlights common pitfalls in understanding the relationship between pressure, density, and altitude.

PREREQUISITES
  • Understanding of basic physics concepts, specifically hydrostatics
  • Familiarity with the ideal gas law and its applications
  • Knowledge of differential equations and their physical interpretations
  • Ability to perform unit analysis for consistency in equations
NEXT STEPS
  • Study the derivation of the ideal gas law and its implications for atmospheric pressure
  • Learn about hydrostatic equilibrium in fluid mechanics
  • Explore applications of differential equations in physical systems
  • Investigate the relationship between temperature, pressure, and density in atmospheric science
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Students of physics, atmospheric scientists, and educators looking to deepen their understanding of pressure dynamics in the atmosphere.

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Homework Statement



a. Consider a horizontal slab of air whose thickness (height) is dz. If this slab is at rest, the pressure holding it up from below must balance both the pressure from above and the weight of the slab. Use this fact to find an expression for dP/dz, the variation of pressure with altitude, in terms of the density of air.

b. Use the ideal gas law to write the density of air in terms of pressure, temperature, and the average mass m of the air molecules. Show, then, that the pressure obeys the differential equation:

dP/dz = - P(mg)/(kT)

Homework Equations





The Attempt at a Solution



R= rho

P_(z+dz) + mg - P_(z) = 0

dP = mg

m = R A dz

dp/dz = R A mg



I don't think that that is right for a because I am completely stuck on how to get it to work with b...
thanks for the help
 
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Hi phrygian! :smile:

(have a rho: ρ :wink:)
phrygian said:
P_(z+dz) + mg - P_(z) = 0

dP = mg

m = R A dz

hmm … you're getting rather confused …

start again, and specify what size of slice you're dealing with …

that way, you'll not only impress the examiner, you'll also avoid confusing yourself! :wink:

in this case, a slice of height dz and area A …

so its mass is … ?

and the forces top and bottom are … ? :smile:
 
phrygian said:
P_(z+dz) + mg - P_(z) = 0
Look at your units. Pressure has units of force/area, m*g has units of force. This equation, as written, doesn't make sense. It is a good idea to always make sure you have consistent units in an expression.
 

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