The figure shows a PV diagram for 2.69 mole of oxygen gas in a sealed

AI Thread Summary
The discussion revolves around calculating the temperatures T3 and T4 for 2.69 moles of oxygen gas in a sealed container, using a PV diagram. The initial temperature is given as 21°C, and the pressure is Pi. The calculations for T3 and T4 involve applying the ideal gas law, but an error was noted in the calculation of T3, specifically regarding the conversion from Kelvin to Celsius. The correct value for T3 should be verified to avoid negative results. Accurate calculations are essential for determining the temperatures in the context of thermodynamics.
billsauce
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Homework Statement


The figure shows a PV diagram for 2.69 mole of oxygen gas in a sealed container. The temperature of state 1 is 21 C. Pressure is Pi. What is T3 and T4?
http://s74.photobucket.com/user/teysure/media/phyiscs.png.html?sort=3&o=0





my attempt at solving the solution:
T3 - P1V1/T1 = P3V3/T3
(1Pi)(.100l)/294K = (1.5Pi)(.05l)/T2
T2 = 220.5K - 273 = 52.5K

T4 - V3/T3 = V4/T4
(.05l)/(220.5K) = (.150l)/(T4)
T4 = 661.5K = 388.5C
 
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billsauce said:

Homework Statement


The figure shows a PV diagram for 2.69 mole of oxygen gas in a sealed container. The temperature of state 1 is 21 C. Pressure is Pi. What is T3 and T4?
http://s74.photobucket.com/user/teysure/media/phyiscs.png.html?sort=3&o=0my attempt at solving the solution:
T3 - P1V1/T1 = P3V3/T3
(1Pi)(.100l)/294K = (1.5Pi)(.05l)/T2
T2 = 220.5K - 273 = 52.5K

T4 - V3/T3 = V4/T4
(.05l)/(220.5K) = (.150l)/(T4)
T4 = 661.5K = 388.5C
When you calculated T3, you made a sign error. 220.5 - 273 is a negative number, and the result is in degrees °C.
 

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