Evaluate the definite integral of the algebraic function. Use a graphing utility to verify your result.
Integral from [1 to 2] of (3/x^2 - 1)
The answer is 1/2
f(x)dx= F(b) - F(a)
The Attempt at a Solution
I tried taking it to make it -x^-3 - 1x as the antiderivative but when I put 2 in and then 1 I don't get the answer.