The Heating of Nichrome Wire in a toaster

AI Thread Summary
A toaster with a Nichrome heating element has a resistance of 70 ohms at 20°C and an initial current of 1.6 A, which decreases to 1.39 A at the final temperature. The voltage remains constant, leading to the equation Io*Ro=If*Rf. The temperature coefficient of Nichrome is 4 * 10^-4 K^-1, which is relevant for calculating changes in resistivity. Participants discuss deriving an equation for resistance as a function of initial and final temperatures, but there is confusion regarding the use of resistivity and the constant involved. The conversation highlights the need to clarify the relationship between resistance, temperature, and resistivity in the context of Nichrome wire.
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Homework Statement



A toaster with a Nichrome heating element has a resistance of 70 ohms at 20oC and an initial current of 1.6 A. When the heating element reaches its final temperature, the current is 1.39 A. What is the final temperature of the heating element?

Homework Equations



V=IR
\alpha=(\rho-\rhoo)/\rho/(Tf-To)

The Attempt at a Solution


I know that the voltage will remain constant therefore:
Io*Ro=If*Rf
I also know that Nichrome's \alpha=100e-8
but I don't really know where to go from here
 
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from <br /> <br /> \alpha = \frac {\rho - \rho_0} {\rho} (T_f - T_0) <br /> <br />

try to derive an equation for R as a function of R_0, T_0, T_f and \alpha
you know the new R from ohms law.

The temperature coefficent of nichrome is 4 *10^{-4} K^{-1}
 
So am I going to be looking at resistivity then? such as \rho=R*A/L ??
 
gc33550 said:
So am I going to be looking at resistivity then? such as \rho=R*A/L ??

yes. Instead of \rho=R*A/L you can use \rho=R*C. You don't know what A and L are anyway, except that they are constant.
 
C as in capacitance? How do I find that?
 
gc33550 said:
C as in capacitance? How do I find that?

no it's just an arbitrary constant
 
would that constant be in my physics book somewhere?
 
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