Undergrad Understanding the Coordinates in the Lagrangian for a Pendulum

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SUMMARY

The discussion centers on the coordinates used in the Lagrangian formulation for a pendulum, specifically referencing Landau's classical mechanics text. The coordinates for the support point are defined as ##\mathbf{r}_p = a(\cos{\gamma t}, -\sin{\gamma t})##, while the radius vector from the support point to the mass is given by ##\mathbf{R} = l(\sin{\phi}, \cos{\phi})##. The final coordinates of the mass ##m## are derived from the sum of these vectors, leading to a comprehensive understanding of the system's dynamics. This clarification resolves the initial confusion regarding the relationship between the harmonic oscillator and the pendulum's coordinates.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with polar coordinates
  • Knowledge of harmonic oscillators
  • Basic concepts of classical mechanics
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  • Study the derivation of the Lagrangian for a simple pendulum
  • Explore the relationship between Lagrangian mechanics and Hamiltonian mechanics
  • Learn about the application of polar coordinates in mechanics
  • Investigate the dynamics of coupled harmonic oscillators
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Students of classical mechanics, physicists interested in Lagrangian dynamics, and educators teaching advanced mechanics concepts.

p1ndol
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So I've been studying classical mechanics and have come across a small doubt with the solution provided to the problem in question from Landau's book. My question is: why are the coordinates for the particle given as they are in the solution? I imagine it has something to do with the harmonic oscillator, but I'd like to properly understand. I appreciate any kind of help, and I'm sorry if this post is somehow incorrect, it is my first one regarding questions.
 

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Did you look at the figure? For instance in (a), the support point ##p## has coordinates ##\mathbf{r}_p = a(\cos{\gamma t}, -\sin{\gamma t})## and the radius vector from ##p## to ##m## has coordinates ##\mathbf{R} = l(\sin{\phi}, \cos{\phi})## then the coordinates of ##m## are nothing but those of the vector ##\mathbf{r}_p + \mathbf{R}##.
 
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Likes vanhees71 and p1ndol
I understand it now, thanks!
 

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