- #1
wii
- 12
- 0
hi there,
how can i show that the lie brocket is not connection?
Many thanx =)))
how can i show that the lie brocket is not connection?
Many thanx =)))
Can you evaluate the following expressions, where X and Y are arbitrary vector fields, and f is an arbitrary smooth function?Actually I check all the properties of the connection and I can not find out any different and I give up =|
The policy around here is that people who ask for help with textbook-style problems have to show a complete statement of the problem, the definitions they're using, and their work so far, so that we can give hints that will help them move past the point where they are stuck.I have another question =)
If we want to prove that V(t) is a geodesic of 6(u,v) OK?
So, I try to prove that by the fact " V(t) is geodesic iff V'' =0 " and also I try to do that by calculate ||V'||^2 = constant.
but both of them did not work =(
is there any different way to prove that V(t) is geodesic ?? please your advice
In LaTeX, you need to use \ instead of /. For example, \sigma instead of /sigma. I also recommend \cos instead of cos.If [tex]f(x)[/tex] is a positive function and
[tex]\sigma(u,v)[/tex] [tex]\eq(f(u)\cos(v),f(u)\sin (v),u)[/tex] then
[tex]\gamma(t)[/tex] = [tex]\sigma(u(t),c)[/tex]
is a geodesic where c is constant between 0 and [tex]\pi[/tex]
that was the question and I tried to calculate the second derivative of /sigma but that did not work and we still have u in the first derivative which means it is not constant
and thank you Fredrik =)