The Mass of a Black Hole versus its volume

AI Thread Summary
A black hole's escape velocity can exceed the speed of light if its mass is sufficiently large, regardless of density. To find the mass needed for a black hole's density to equal that of water (1 g/cm³), one can use the Schwarzschild radius formula. The calculations reveal that the minimum mass of a black hole is approximately 1.33 x 10^8 solar masses. However, the interior volume of a black hole cannot be accurately calculated using traditional Euclidean geometry due to the non-flat nature of space within the event horizon. This highlights the complexities involved in understanding black hole properties.
oldspice1212
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A clump of matter does not need to be extraordinarily dense in order to have an escape velocity greater than the speed of light, as long as its mass is large enough. You can use the formula for the Schwarzschild radius Rs to calculate the volume 4/3piRs^3 inside the event horizon of a black hole of mass M.

What does the mass of a black hole need to be in order for its mass divided by its volume to be equal to the density of water (1 g/cm^3) ?So I have the density which = mass/volume = 1 g/cm^3

I know I'm suppose to find the mass but then how do I know what the volume is?
If the volume formula is 4/3pir^3, I'm having trouble with finding radius now, since I don't have the volume, I'm really frustrated about this question.Also using Schwarzschild radius formula Rs = 2Gm/c^2 seems useless because I don't have mass now?! Err so I need mass and volume but all I have is density?!
 
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SOLVED IT...

Rs = (3km)x M/Msun convert 3km to 3x10^5 cm...

density = mass/volume = M/ 4/3 piR^3

density = 3M/ 4pi ((3x10^5 cm)M/Msun)^3

...

M/Msun = root (3Msun/4pi(density)(2.7x10^16))

= 1.33x10^8 Msun

Took a while but finally got it, and this is how if anyone is interested.
 
With that you could calculate the minimum possible mass of a black hole. Is there one? Could you just shove two neutrons together really hard and have them form an event horizon?
 
Thank you Oldspice1212! I was looking for how to solve this question too!

Could you tell me where you got Rs = 3km x M/Msun? and where the 3km came from?



As well, for this section of what you wrote: "M/Msun = root (3Msun/4pi(density)(2.7x10^16))"

I plugged this in as 3rdroot(3*(2*10^30) / 4pi(1)(2.7*10^16)) but I did not get 1.33*10^8 Msun, Did I do it correctly?
 
What would be the minimum mass of a black hole with a volume of 225 m^3
 
JustinAlger said:
What would be the minimum mass of a black hole with a volume of 225 m^3
Welcome to PF.

Can you use the equations in the posts above to answer your question?
 
Note also that this question doesn't really make sense, since the interior volume of a black hole can't be calculated using a Euclidean formula. That space isn't flat there is kind of an important point...
 
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