The operator of momentum (layman question)

[paulzhen]

I found two "forms" of it:

p=$\frac{\hbar}{i}$$\frac{d}{dx}$

p=-i$\hbar$$\frac{d}{dx}$

how could they be the same??

 

[ZapperZ]

Multiply the right hand side of the first equation with i/i.

Zz.

 

[paulzhen]

oh...yes thanks a lot