The Physics of Stopping: Mercedes Commercial 80 mph in 4 Sec

  • Thread starter Thread starter krehbester
  • Start date Start date
AI Thread Summary
The discussion centers on the stopping distance of a vehicle moving at 80 mph, which is calculated to be 235 feet under constant deceleration. The average speed during the stop is 58.7 feet per second, leading to this distance when stopping in 4 seconds. The key factor influencing stopping distance is the friction coefficient between the tires and the ground, which must be 0.95 to achieve a deceleration of 20 mph per second. This means that while size and weight do not directly affect the stopping distance when time and speed are known, the friction coefficient is crucial. Understanding these dynamics is essential for evaluating vehicle performance in emergency braking scenarios.
krehbester
Messages
1
Reaction score
0
There's a Mercedes commercial that claims one of their cars can stop from 80 mph in 4 seconds. My question is: if you stop any object moving at 80 mph in 4 seconds will it always take the same distance to stop no matter the size or weight? If so how far?
 
Physics news on Phys.org
If they give you the time and speed, the size and weight are already accounted for.

80mph is 117 fps. Assuming constant deceleration, the average speed is 58.7fps and therefore the distance is 235 ft.

The primary factor in stopping distance is the friction coefficient of the tires/ground. In this case, to decelerate by 20mph every second, you need a friction coefficient of .95, as g is 21 mph/s.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
Back
Top