The Power of 0: Is It Just An Agreement?

  • Thread starter Thread starter TSN79
  • Start date Start date
  • Tags Tags
    Power
AI Thread Summary
The discussion centers on the concept of a number raised to the power of zero, which is defined as one, and whether this is merely an arbitrary agreement. Participants argue that this definition is not just a simple agreement but is rooted in mathematical consistency and properties, such as maintaining the validity of exponent rules. The reasoning includes that if x^n * x^0 must equal x^n when n is a positive integer, then x^0 must equal one for the property to hold true. Additionally, alternative definitions using series also support this conclusion. Overall, the consensus is that while definitions in mathematics are agreed upon, they are not arbitrary and serve essential functions in mathematical theory.
TSN79
Messages
422
Reaction score
0
We all know that a number to the power of 0 equals 1. Bit I heard this is only a definition, iow something that has just been agreed on. But how can such a thing be done? If one had agreed that it would equal 0 instead, I suppose many mathematical proofs and stuff would be different, things that can't be done suddenly would be possible. Is it really the case that this is just an agreement?
 
Mathematics news on Phys.org
TSN79 said:
We all know that a number to the power of 0 equals 1. Bit I heard this is only a definition, iow something that has just been agreed on. But how can such a thing be done? If one had agreed that it would equal 0 instead, I suppose many mathematical proofs and stuff would be different, things that can't be done suddenly would be possible. Is it really the case that this is just an agreement?
It is according to the definition of raising a number to a power that a nonzero number to the zero power is equal to one, just like it is according to this definition that a x to the second power is x times x. It is really not an unnatural definition. We know that x^n\times x^m=x^{m+n}. If we want this to be true then x^n\times x^0=x^n \rightarrow x^0=1. Alternitively, powers can be defined by series. In this case b^x=e^{x\ln{b}} and
e^x=1+\sum_{n=1}^{\infty}\frac{x^n}{n!}
So
b^x=e^{0\ln{b}}=1+\sum_{n=1}^{\infty}\frac{0^n}{n!}=1
 
Last edited:
TSN79 said:
We all know that a number to the power of 0 equals 1. Bit I heard this is only a definition, iow something that has just been agreed on. But how can such a thing be done? If one had agreed that it would equal 0 instead, I suppose many mathematical proofs and stuff would be different, things that can't be done suddenly would be possible. Is it really the case that this is just an agreement?

Drop the word "just" and I will agree with you. In mathematics, everything in mathematics is a definition but not "just" a definition! As Leonhard Euler said, it is not "an unnatural definition".

From the simplest case, xn with n a positive integer, where we can think of xn as meaning "x multiplied by itself n times" (which is, after all, "just" a definition), we find that xnxm= xn+m because "n times" followed by "m times" is the same as "n+ m times".

If we want that very nice property to continue to be true even if m is 0, we must have xnx0= xn+ 0. But n+0= 0 so we have xnx0= xn. As long as x is not 0, we can divide both sides by xn and get x0= 1.

That is why we define x0 to be 1 (and only define it for x not equal to 0).
 
HallsofIvy said:
Drop the word "just" and I will agree with you. In mathematics, everything in mathematics is a definition but not "just" a definition! As Leonhard Euler said, it is not "an unnatural definition".
From the simplest case, xn with n a positive integer, where we can think of xn as meaning "x multiplied by itself n times" (which is, after all, "just" a definition), we find that xnxm= xn+m because "n times" followed by "m times" is the same as "n+ m times".
If we want that very nice property to continue to be true even if m is 0, we must have xnx0= xn+ 0. But n+0= 0 so we have xnx0= xn. As long as x is not 0, we can divide both sides by xn and get x0= 1.
That is why we define x0 to be 1 (and only define it for x not equal to 0).
Excellent explanation thank you. However N+0=N not N+0=0.
 
HallsofIvy said:
Drop the word "just" and I will agree with you. In mathematics, everything in mathematics is a definition but not "just" a definition! As Leonhard Euler said, it is not "an unnatural definition".
From the simplest case, xn with n a positive integer, where we can think of xn as meaning "x multiplied by itself n times" (which is, after all, "just" a definition), we find that xnxm= xn+m because "n times" followed by "m times" is the same as "n+ m times".
If we want that very nice property to continue to be true even if m is 0, we must have xnx0= xn+ 0. But n+0= 0 so we have xnx0= xn. As long as x is not 0, we can divide both sides by xn and get x0= 1.
That is why we define x0 to be 1 (and only define it for x not equal to 0).

i was confused if 1^0 = 1 and 1^n = 1 (n= 1,2,3...)
then o = 1,2,3...
 
debeng said:
i was confused if 1^0 = 1 and 1^n = 1 (n= 1,2,3...)
then o = 1,2,3...
That's like saying 0*0 = 0 and 0*n = 0 (n= 1,2,3...) then 0 = 1,2,3...

Think about why that isn't true for a moment.
 
This is the example I usually think of when this comes up: 1=xn/xn=xn-n=x0.
 
StatusX said:
This is the example I usually think of when this comes up: 1=xn/xn=xn-n=x0.
That works also.
 
Another way I like to think of it as a notation with xn, where you factor out an x each time n decreases. If x = 3,

x3 = 27

if you factor out three 27/3

x2 = 9

factor out three again 9/3

x1 = 3

and factoring three again 3/3

x0 = 1

I really had trouble visualing "raised to a zero power" and "negative exponents" until I "just" thought of it as a notation.
 

Similar threads

2
Replies
91
Views
6K
Replies
47
Views
6K
Replies
5
Views
2K
Replies
55
Views
5K
Replies
7
Views
3K
Back
Top