The product of exponential and a uniform random variables

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The discussion focuses on proving that U(X+Y) has the same distribution as X, where X and Y are independent exponential random variables and U is uniformly distributed on (0,1). It is established that X+Y follows a gamma distribution with parameters (2, λ). The challenge lies in handling the product U(X+Y) effectively. A suggested approach is to compute the Laplace transform of Z = U(X+Y) and condition on U to simplify the analysis. The thread emphasizes the need for a clear method to derive the distribution of Z.
MathBubble
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Homework Statement



I'm trying to show that U(X+Y) = X in distribution, where X and Y are independent exp(λ) distributed and U is uniformly distributed on (0,1) independent of X+Y.

Homework Equations


The Attempt at a Solution


X+Y is gamma(2,λ) distributed. But I can't figure out how to deal with this product.
 
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MathBubble said:

Homework Statement



I'm trying to show that U(X+Y) = X in distribution, where X and Y are independent exp(λ) distributed and U is uniformly distributed on (0,1) independent of X+Y.


Homework Equations





The Attempt at a Solution


X+Y is gamma(2,λ) distributed. But I can't figure out how to deal with this product.

Get the distribution of Z = U(X+Y) by computing its Laplace transform
\tilde{Z}(s) \equiv Ee^{-sZ}.
Hint: condition on U.

RGV
 
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