The speed of light and the uncertainty principle

JoAuSc
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The Heisenberg uncertainty principle says that

h-bar/2 <= dE * dt.

Let's say we have this device that emitted very low energy radio waves. Does that mean there'd be a significant probability of these photons traveling faster than light?
 
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JoAuSc said:
The Heisenberg uncertainty principle says that

h-bar/2 <= dE * dt.

It's more subtle than that. We can show from general principles that

\frac{\Delta A}{|d\langle A\rangle/dt|}\Delta E \ge \hbar/2

If we now define the bit on the left as \Delta t, we get the oft-quoted uncertainty relation between time and energy.

The justification for making that identification is that it's the average time taken for the expectation of the operator A to change by its standard deviation, so it's roughly the time scale to measure a change in A.
 
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