The units of a cartesian product?

chuy52506
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Find all units in Z12 X Z6 and their inverses.

What i did was find the units of Z12 which are 1,11,5,7 then the ones of Z6 which are 1,5 and take the cartesian product of those two sets?
 
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Yes, that would be correct!
 
So there would be eight?
1,1 1,5 11,1 11,5 5,1 5,5 7,1 and 7,5?
 
Instead of asking this, why don't you try to prove that the units of the product are precisely the pairs of units?
 
Because it helps to do an example before. So is this correct?
 
micromass already answered that question. If you're still not entirely sure, my advice stands: prove it! (it's quite easy; it's a matter of writing out the definitions)
 
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The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...

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