Dmitry67 said:
Why not?
Say, density P=1/t everywhere in 3D space.
So P(X,Y,Z)=1/t
Here is an example of singularity infinite in size at t=0
This is spacey!
I have to think some more before 'computing' infinite sets... And jump on to the
much easier part –
infinite singularity!
Okay, maybe it’s because I think in 'pictures' and you think (
the right way) in mathematics, that this doesn’t work for me. I’m going to try to get as close to your math as possible.
The density of a material is defined as its mass per unit volume:
\rho = \frac{m}{V}\,
I take it the same rule goes for the (infinite) universe? Ok, then if we then take the
'2D Balloon Surface' as an analogy for universe, and use the Earth as the balloon (
and forget about mass 'inside', and place all mass on the surface of Earth instead, and hope that it will work? 
).
Now the surface of Earth will weigh 5.9736 × 10e24 kg at a radius of 6371 km (
still hope that it will 'hold'!? 
). For this to turn into a singularity, we use the Schwarzschild solution:
r_{s} = \frac{2GM}{c^{2}}
I skip the math

, and pick the right answer from the web, and we get that the radius has to shrink from
6371 km to
9 mm (peanut-size), for the Earth mass to turn into a singularity!
Maybe this is not applicable on a 3D space? But I hope you see what I aiming at? The shrinking of volume to get higher density, to finally reach the Schwarzschild 'border'... and then I remember that you just mentioned that
volume is
not applicable to infinity, man this is weird...
But, now another question pops up! In an infinite universe, with infinite matter – how can you avoid the thing from turning into a
singularity immediately at t=0+1plank... Schwarzschild would go bananas??