TheoMech - rolling a ball down a curve

Click For Summary
SUMMARY

The discussion centers on analyzing the forces acting on an object rolling down a curve defined by a function y=f(x) in a theoretical mechanics context. The user seeks to determine the independent forces Fx(x,f(x)) and Fy(x,f(x)) at a given position on the curve, assuming no friction and gravity acting only in the y-direction. The conversation explores the application of Lagrangian mechanics to derive acceleration in both directions and discusses the normal force's relationship to the curve's gradient. Ultimately, it concludes that when the x-axis is oriented perpendicular to gravity, there is no force acting in the x-direction.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with vector calculus
  • Knowledge of gravitational forces and their components
  • Basic concepts of dynamics and motion along curves
NEXT STEPS
  • Study Lagrangian mechanics for deriving equations of motion
  • Explore vector calculus applications in physics
  • Learn about gravitational force decomposition in dynamics
  • Investigate the mathematical modeling of curves and their properties
USEFUL FOR

This discussion is beneficial for students and professionals in theoretical mechanics, physics enthusiasts, and anyone interested in the dynamics of objects moving along curved paths.

K.J.Healey
Messages
622
Reaction score
0
This isn't a homework question (im not in school) but its nearly one for a Theomech class, or maybe just dynamics. Maybe I'm just not seeing it.


Assume you have a hill that's defined by some part of a function y=f(x) (like exponentially decreasing, or a sine wave)

and you put an object on top and let it move down the curve.
assume no friction, there is some gravity force in the y direction only.

What are the independent forces of the object at a given x direction?

so I am looking for Fx(x,f(x)) and Fy(x,f(x)) so get the force given some euation describing the curve and a position.

Would I use lagrangian mechanics to pull out the accel in each direction? or what...

thanks
 
Last edited:
Physics news on Phys.org
heres what I've come up with so far

assuming the equation f(x), the vector describing the direction of increase from the current point xo, would be :

Vi = {f(xo+dx) - f(xo), xo} (haha, I've seen that somewhere before...)

ok, so the normal force would be orthogonal to this vector.

Vn = -dx*i + (f(xo+dx)-f(xo))*j

so Fn = |Fn|*Vn
and Fn_x = -dx

wait wait wait, so this DOESNT feel a force in the X direction? I mean if take the limit and dx->0... am I doing this the wrong way?

Its basically looking at the gradient of something... why don't i remember this stuff...
 
If you are referencing your x-axis perpendicular to g, then no there is no force in the x direction. Personally, I would set the axis such that x is along the average of the function of the path of decent, y being perpendicular, g will be a resultant of two vectors, Gx and Gy. I'm not really sure what your trying to do though, so...
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
43
Views
4K
  • · Replies 32 ·
2
Replies
32
Views
3K
Replies
39
Views
3K
  • · Replies 97 ·
4
Replies
97
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
24
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
5K