Therhelp modynamics and the equilibrium constant

AI Thread Summary
The discussion centers on the relationship between thermodynamics and the equilibrium constant (Keq) in chemical reactions. Participants seek clarification on whether Keq refers to Kc, Kp, Ksp, Kf, or Kd, with a focus on whether it is always Kc for any reaction. It is noted that Kc is used for concentration, while Kp is for gas-phase reactions, and other forms like Ksp, Kf, and Kd serve specific purposes. Additionally, there is a request for the derivation of the equation G = *(G) + RT ln(Keq), emphasizing the need for a solid understanding of Physical Chemistry to grasp the concepts. The discussion highlights the importance of context in determining which equilibrium constant to use based on the type of reaction.
mcato_O
Messages
3
Reaction score
0
Therhelp ! modynamics and the equilibrium constant

Thermodynamics and the equilibrium constant

Okay I have a question about the equation (* means change) (*() means stander condition) so [G=*(G)+RT ln (Keq)] or just equation *(G)= - RT ln(Keq)
So what dose the (Keq) stander for? Kc? Kp? Ksp?? Kf or Kd

Is it always Kc regardless the chemical reaction? (that’s what my prof told me)
And then use the equation Kp=Kc (RT)^*n to convert K value?

Or is does Keq depends on the chemical reaction Kc for solution Kp for Gas?(from the textbook)

And can someone please derived the equation [G=*(G)+RT ln (Keq)] for me?
Where is it come from and why does it makes sense?
 
Physics news on Phys.org
The derivation is a bit extensive, and you'll have to cover some ground in Physical Chemistry before you can make sense out of this particular topic.

The Kc,Kp,Ksp,Kf,Kd are the equilibrium constants with respect to the concentration Kc, and pressure Kp; the rest are specific forms uniquely suited to the reaction dynamics. That is, they be in terms of the concentration or pressure. Ksp is in reference to the solubility, Kf to complex ion formation, Kd to dissociation.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top