Thermal expansion of a copper cylinder

[dan_and_sim]

Homework Statement

A copper cylinder is initially at 20.0 degrees c At what temperature will its volume be 0.150 % larger than it is at 20.0 degrees c

Homework Equations

delta v = Beta vo (delta T)
dv= beta vo dt

The Attempt at a Solution

ive found an answer of 49.41 degrees c

I believe its from manipulating the second equation to
beta = dv / (vo dt)

does this seem right?
any help here would be great thanks in advance

 

[jfislove]

Yeah I got the same answer, MP says it's right!