Thermal expansion of oil overflowing from a tank

  • Context: Engineering 
  • Thread starter Thread starter Doct3r88
  • Start date Start date
  • Tags Tags
    Expansion Oil Thermal
Click For Summary
SUMMARY

The discussion centers on the calculation of thermal expansion of oil and the proper conversion from linear to volumetric expansion. The user initially multiplied the volumetric expansion of oil by 3, which was incorrect since the volumetric expansion was already defined. The correct approach involves understanding that linear expansion must be converted to volumetric expansion before performing any calculations. The final corrected value for the volumetric expansion of oil is 20.3717 mm3 × 10-3.

PREREQUISITES
  • Understanding of thermal expansion concepts
  • Familiarity with volumetric and linear expansion calculations
  • Knowledge of the properties of oil and steel
  • Basic mathematical skills for unit conversions
NEXT STEPS
  • Research the formulas for linear and volumetric thermal expansion
  • Learn about the thermal expansion coefficients for different materials
  • Explore practical applications of thermal expansion in engineering
  • Study the effects of temperature changes on fluid dynamics
USEFUL FOR

Engineers, physicists, and students studying material science or thermodynamics who are interested in understanding thermal expansion principles and their applications in real-world scenarios.

Doct3r88
Messages
2
Reaction score
0
Homework Statement
A waste handling machine requires a cube shaped steel oil tank of side length 100mm to be designed which will be subject to a fluid pressure of 80MN/m². The oil tank as an overflow valve fitted to the top of the tank, the tank is completely filled with oil at an optimum operating temperature of 50°C, under your investigations in the R&D dept it was found that the oil temperature could rise to 78°C depending on the operating time and external environmental temperature. Ignoring the fluid pressure, determine how much oil will overflow from the tank. Take the volumetric coefficient of expansion of the oil as 764 x 10-6 °C -1 and the linear coefficient of expansion of steel as 12 x 10-6 °C -1.
Relevant Equations
∆L=αL_0 ∆T
δV_o=V_o*β*∆T
Just wanted to know if I was barking up the wrong bush or not with my working out if anyone could help?
1700755939266.png
 
Physics news on Phys.org
You are multiplying the volumetric expansion of the oil by 3. I am not sure why.
It the intention is to convert it from a linear expansion to a volumetric expansion, then it is wrong, because at the bottom of page 1 you are defining it ( ##a_0## ) to be volumetric already.
 
Last edited:
Ah yes I see what you're saying I think I misread the example given and to go from linear to volumetric I would have had to multiply by 3 thank you. Amended now to get 20.3717mm^3*10^-3.

My doubt was over whether I had gone about working out the expansion of the steel tank correctly or whether I should have converted the steel linear expansion into volumetric then subtracted them from one another.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 56 ·
2
Replies
56
Views
6K
Replies
18
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K