I really don't want to get involved in these threads (the other being
"How does the Higgs scalar potential evolve with temperature?") because I only have a rough idea of how thermal field theory works, and they deserve technically correct answers. However, I cannot abide the growing confusion taking shape here.
In the other thread,
@nikkkom said this:
nikkkom is making a point of terminology. The Higgs field can have zero expectation value - zero e.v. But the vacuum is defined as the state of lowest energy, and because of the Higgs potential, the state of lowest energy is one where the field has an expectation value greater than zero - nonzero e.v. So the Higgs vacuum has a nonzero e.v., and we say that the Higgs has a nonzero vev - vacuum expectation value.
It is not just an accident that this state is called a vacuum. Recall that the colloquial meaning of vacuum is emptiness - no particles around. In quantum field theory, a particle is something that carries a quantum of energy in addition to what's in the ground state. You can formally try to treat the zero e.v. state of the Higgs field as the ground state, but you find that you need an infinite number of particles on top of that to describe the actual state of minimum energy, which has nonzero e.v.
So instead we take the state with nonzero e.v. as the vacuum, and define presence or absence of particles with respect to that state.
I presume that nikkkom is thinking of all this when he says, there is no zero vev of the Higgs field. It can have zero ev, but not zero
vacuum ev - that state is not the ground state, it is unstable. And
@jtlz has jumped to the conclusion that the thermal vacuum also has a nonzero vev.
But this is not true! Within thermal field theory, there is a concept of thermal vacuum with respect to which the Higgs field can have zero vev. That's where my understanding stops, really. Presumably what might appear as a plasma of particles, if defined with respect to some other reference state, has here been absorbed into the definition of vacuum. That makes sense because of particle/field duality; a plasma of particles is going to have an alternative characterization as a superposition of field states. It is interesting that the field can be in a state of nonzero
temperature but still have zero e.v.; I don't know if there's some mathematical sleight of hand there.
The fact that e.g. the electroweak bosons now have zero mass in this situation suggests that there is something in common with the usual, zero-temperature vacuum, because the same relation (mass proportional to Higgs vev) still applies. On the other hand, one may also hear that particles in the electroweak plasma have a finite "thermal mass". I don't know if that's in addition to the zero mass I just mentioned, or if these are alternative pictures with alternative definitions of mass.
I will say one more thing: the thermal vacuum is globally defined, like the usual zero-temperature vacuum. That might be fine for the early universe, which by hypothesis is hot everywhere. But the question in this thread asks, what happens if a violent collision creates a finite high-temperature region in which electroweak symmetry is restored. How do you model that?
@protonsarecool mentions the Keldysh formalism, which sounds right, but I have no idea of the details.