Thermodynamic properties of a liquid-gas mixture

AI Thread Summary
To calculate the thermodynamic properties like entropy and enthalpy of a 70% steam and 30% air mixture at 90°C and 10 MPa, it's important to consider that at this pressure, water will primarily exist in the liquid state. The equilibrium vapor pressure of water at 90°C is approximately 0.07 MPa, indicating that while some water vapor will be present, most will be liquid. The mixture can be approximated as an ideal gas for calculations, but the presence of liquid water complicates this assumption. The mass fractions of air and water in the gas phase can be determined based on the total pressure and the partial pressure of water vapor. Understanding these properties is crucial for accurate thermodynamic analysis of the liquid-gas mixture.
Rafe Zayed
Messages
6
Reaction score
0
How can I calculate thermodynamic property like entropy and enthalpy of 70% steam and 30% air mixture ?( at about 90 degree Celsius and 10 MPa)
 
Engineering news on Phys.org
The boiling point of water at 10 Mpa is 311°C
 
Rafe Zayed said:
How can I calculate thermodynamic property like entropy and enthalpy of 70% steam and 30% air mixture ?( at about 90 degree Celsius and 10 MPa)
Welcome to the PF.

This is a pretty useful website that you may find helpful in your learning: http://www.thermopedia.com/content/1150/

:smile:
 
Do you mean 30 mole %? Are you willing to assume that the mixture is an ideal gas mixture? What are the reference states of the air and water relative to which you desire to determine the entropy and enthalpy?
 
Chestermiller said:
Do you mean 30 mole %? Are you willing to assume that the mixture is an ideal gas mixture? What are the reference states of the air and water relative to which you desire to determine the entropy and enthalpy?
No I mean 30% by mass fraction.
And at this high pressure ,water will be liquid. So I am not sure whether I can treat them as gas mixture or liquid gas mixture.
Any suitable reference point will do.Basically I want to find the property of a liquid -gas mixture
 
What is the equilibrium vapor pressure of water vapor at 90 C?
 
Chestermiller said:
What is the equilibrium vapor pressure of water vapor at 90 C?
According to internet I found it to be around 70000 Pa
 
Rafe Zayed said:
According to internet I found it to be around 70000 Pa
Good. So that's about 0.07 MPa. If you're willing to tentatively approximate the gas phase as an ideal gas mixture, then that would be the partial pressure of water vapor in the gas phase. And at a total pressure of 10 MPa, what would be the mole fraction of water vapor in the gas phase? From these results, what would be the mass fractions of air and water in the gas phase? On the basis of 1 kg of water and air, what would be the mass of air? What would be the mass of water vapor in the gas phase? How much water would that leave for the liquid phase?
 
Chestermiller said:
Good. So that's about 0.07 MPa. If you're willing to tentatively approximate the gas phase as an ideal gas mixture, then that would be the partial pressure of water vapor in the gas phase. And at a total pressure of 10 MPa, what would be the mole fraction of water vapor in the gas phase? From these results, what would be the mass fractions of air and water in the gas phase? On the basis of 1 kg of water and air, what would be the mass of air? What would be the mass of water vapor in the gas phase? How much water would that leave for the liquid phase?
Sorry ,I didn't get that.At this pressure will there be any water vapour?Won't all the water vapour turn into liquid?
 
  • #10
Rafe Zayed said:
Sorry ,I didn't get that.At this pressure will there be any water vapour?Won't all the water vapour turn into liquid?
Not all, but most.
 
Back
Top