Thermodynamics: Determine pressure in the tank of a manometer

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SUMMARY

The discussion centers on determining the pressure in the tank of a manometer, specifically the relationship between the pressure in the tank (Pt) and the pressure at point A. The professor clarified that while Pt is approximately equal to the pressure at point A, the weight of the gas in the connecting tube must be considered for precise calculations. The density difference between the gas and the liquid makes this correction trivial but necessary for exact measurements. Additionally, the pressure inside the tank varies with the "depth" of the gas above the measurement point, necessitating an analysis of hydrostatic pressure changes in both the gas and liquid.

PREREQUISITES
  • Understanding of basic thermodynamics principles
  • Familiarity with manometer design and function
  • Knowledge of hydrostatic pressure concepts
  • Basic understanding of gas laws and density variations
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  • Study hydrostatic pressure calculations in fluids
  • Learn about manometer types and their applications
  • Explore the effects of gas density on pressure measurements
  • Investigate the principles of gas laws and their implications in fluid mechanics
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Students in physics or engineering, professionals working with fluid dynamics, and anyone interested in precise pressure measurement techniques in manometers.

mhrob24
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Homework Statement
Find the pressure (Pt) in the tank of the manometer
Relevant Equations
P= W/A = density x gravity x height
I was watching a YT video getting prepared for class this coming semester, and in the video, this diagram of a manometer was drawn (see image at end of message). The professor stated that the pressure in the tank (Pt) is = to the pressure at point A. Following this, he said that technically speaking, it wasn’t EXACTLY equal because of the weight of the gas in the portion of the tube connected to the tank, but because the density of the gas is much smaller than the density of the liquid, it would make a trivial difference.

I THINK I get what he’s saying but I want to be sure. So basically, the “tank” here is considered to be just the square tank…..not including the connection tube (even though that tube is exposed to the gas in the tank). So in all reality, if you wanted to truly calculate the EXACT pressure at point A, you would have to include the weight of the gas in that portion of the tube above point A. Is this correct? That’s the only way I can make sense out of what was said in the video…

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I believe that you are both correct.
Just like it happens in the ocean, the pressure inside the tank will vary with the "depth" at which the point we want to measure is sumerged in the mass of gas, plus the static pressure inside the tank.
 
You may need to analyse the hydrostatic pressure change with height in both the liquid and the gas. The gas has variable density which will make it interesting.
 

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