Thermodynamics - Energy analysis of piston-cylinder device

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SUMMARY

The discussion focuses on the energy analysis of a piston-cylinder device in thermodynamics, specifically addressing homework problems related to boundary work calculations. The key values identified include a pressure of 500 kPa and a volume of 0.0551898 m³. The participant successfully calculated part (a) as 22.61 kJ and recognized that part (c) corresponds to the saturation temperature at 500 kPa, which is 151.8°C. However, they encountered difficulties in solving part (b) and sought clarification on the necessary intensive properties and the numerical integration method for boundary work.

PREREQUISITES
  • Understanding of thermodynamic properties, specifically pressure and volume.
  • Familiarity with the concept of boundary work in thermodynamics.
  • Knowledge of ideal gas laws and real gas behavior.
  • Basic calculus for numerical integration techniques.
NEXT STEPS
  • Study the principles of boundary work for real gases in thermodynamic systems.
  • Learn about numerical integration methods applicable to thermodynamic equations.
  • Explore the use of property tables for real gases to identify intensive properties.
  • Review the ideal gas law and its applications in various thermodynamic processes.
USEFUL FOR

Students studying thermodynamics, particularly those working on energy analysis of piston-cylinder devices, and educators seeking to clarify concepts related to boundary work and real gas behavior.

eh87
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Hello :)

I'm having trouble working on this homework question (please see attachment). The answers are supposed to be
a) 22.61 KJ
b) 36.79 KJ
c) 151.8*C

I solved (a) and I noticed that the answer to (c) is that saturation temperature at 500kPa, but I just cannot get (b)! In fact, I'm not really sure I even know what's given for part (b). Obviously P=500kPa, but what else is known? Would Vb = 0.6(Va) = 0.0551898 m^3 ? It seems like I need another intensive property (other than P) to identify the state as a start.

help :confused:
 

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I just read the sticky about homework. Sorry.
 
So I worked on it some more, just trying to understand the darn thing.. and yes, [tex]V_{b}[/tex] = 0.0551898 m^3. Now which formula to use for boundary work?

For constant temp and an ideal gas, I know the formula:
[tex]W_{b}[/tex] = [tex]\int[/tex][tex]mRT/V[/tex]dV = mRT*ln([tex]V_{2}[/tex]/[tex]V_{1}[/tex])

But prof said that for real gases undergoing an isothermal process, the integral in the boundary work equation "would be done numerically." What does that mean??
 

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