1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Thermodynamics help

  1. Oct 25, 2005 #1
    Hello; i'm having a bit of difficulty with a problem here;

    Compressed helium, supplied through a throttle at a pressure of 10 bar and a temperature of 350K, is used to charge a 5 litre gas cylinder. Initially the cylinder contains helium at pressure of 2 bar and a temperature of 290K. Given that the heat loss from the cylinder is negligible during this process, calculate how many mol of helium are added to the contents of the cylinder. refer to;
    W + Q = (delta)Ub - (delta)M(ha) + (delta)Mg(zb-za) - 1/2(delta)M(Ca)^2
    Where W is the shaft work, Q the heat input between points a and b, Ca is the speed at a and ha is the enthalpy per kg at a.

    Any help would be greatly appreciated! thank you
     
  2. jcsd
  3. Oct 25, 2005 #2

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    You should explain all the terms. zb-za appears to be a height difference. Are we to assume that the height difference is 0?

    You should show what you have done so far. What is the condition for the flow to stop? Is there any work done? What does the left side amount to?

    AM
     
  4. Oct 25, 2005 #3
    (delta)Mg(zb-za) is supposed to be the potential energy component of the system. And (delta)Ub is the increase in internal energy of the gas in the fixed volume

    What i thought is that i could let W and Q go to zero and that the system stops flowing when the pressure in the cylinder equals the pressure coming into the system, so 10bar or 1MPa. so

    W + Q = 0 = (delta)Ub - (delta)M(ha) + (delta)Mg(zb-za) - 1/2(delta)M(ca)^2
    where;
    zb = za; so zb -za =0
    and ha = ua +vP, then (delta)M(ha) = Ha = Ua + VPa <-- does that make sense?

    0 = ((delta)Ub-Ua) + V(delta)Pa - 1/2(delta)M(ca)^2

    Now i'm stuck; i don't really know what to do from here.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Thermodynamics help
  1. Thermodynamics help. (Replies: 8)

  2. Thermodynamics Help (Replies: 1)

  3. Thermodynamics Help (Replies: 1)

  4. Thermodynamics - help (Replies: 1)

Loading...