1. The problem statement, all variables and given/known data A 3.6-kg block of ice originally at 263 K is placed in thermal contact with a 13-kg block of silver (cAg = 233 J/kg-K) which is initially at 1006 K. The H2O and silver system is insulated from any other heat transfer. 1)At what temperature will the system achieve equilibrium? 2)What will be the phase of the H2O at equilibrium? CONSTANTS g = 9.81 m/sec2 π = 4*arctan(1) Atmospheric Pressure = 101,300 Pa Density of Freshwater = 1000 kg/m3 Density of Saltwater = 1028 kg/m3 Specific Heat Capacity of Water = 4186 J/K*kg Specific Heat Capacity of Ice = 2200 J/K*kg Latent Heat of Fusion for Water = 333,400 J/kg Latent Heat of Vaporization for Water = 2,260,000 J/kg Gas Constant R = 8.134 J/mol-K σb = 5.670 X 10-8W m-2K-4 k = 1.37 X 10-23 J/K 0°C = 273.15K 2. Relevant equations Q=m*c*ΔT Q=m*C 3. The attempt at a solution In the attachment below. As a note I used the specific heat of water(4186 J/K*kg) for C sub water,T sub i for water as 373.15 K and T sub i for silver as 1006 K. I used the fact the heat from the block of silver is released and absorbed by the block of ice. The ice will have to raise its temperature of 263 K to 273.15 K, then it go through a phase change turning to water, then the waters temperature is raised to 373.15 K, then the water goes through another phase change to turn into steam, the final temperature of the steam is then the temperature of the system in thermal equilibrium. I made the previous assumptions due to the block of silver is at 1006 K which is 723 °C(way above the boiling point of water). The first time I worked out the problem I got a ridiculous answer(it came out to a figure that suggested the system increased in temperature). I then changed a few signs, which then gave me a more reasonable answer, that still gave me a wrong answer. I'm starting think that the ideal gas law may play a part in this, since the water has turned into steam.