Thermodynamics problem, help calculate the energy transfer

AI Thread Summary
A 5 kg mass of steam in a piston cylinder undergoes expansion, transitioning from an initial specific energy of 3000 kJ/kg to a final specific energy of 2500 kJ/kg, with a heat transfer of 80 kJ and 10 kJ of work added by a paddle wheel. The energy transfer by work from the steam on the piston can be calculated using the equation dE = del Q - del W. After correcting for units and multiplying the specific energies by the mass, the change in energy is found to be -2500 kJ. The initial calculation mistakenly represented the work done by the piston rather than the work done by the steam. Proper attention to units and dimensions is crucial for accurate thermodynamic calculations.
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Homework Statement



A mass of 5 kg of steam is contained within a piston cylinder assembly. The steam undergoes an expansion from its initial state with e1 = 3000 kJ/kg to its final state with e2 = 2500 kJ/kg. During the process there is a heat transfer of 80 kJ to the steam. Also, a paddle wheel transfers 10 kJ of work to the steam. Calculate the amount of energy transfer by work from the steam on the piston during the process.

Homework Equations



dE = del Q - del W

The Attempt at a Solution



Would this be correct?
W = del Q - dE
= (80kJ + 10kJ) - (2500 kJ/kg - 3000 kJ/kg)
W = 590 kJ

I don't believe this is correct but it's all I have been able to come up with so far. Any guidance is appreciated
 
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e1 and e2 are specific energies. Multiply them by the steam mass.

You can not sum [kJ] and [kJ/kg].

Watching the dimensions in formulas is a great way to verify your solution.
 
sorry for my half asleep attempt...

Maxim Zh said:
e1 and e2 are specific energies. Multiply them by the steam mass.

You can not sum [kJ] and [kJ/kg].

Watching the dimensions in formulas is a great way to verify your solution.

so after multiplying the steam mass buy each of the energies would I just take the difference?

such that:

m*e2 - m*e1

(5kg)(2500 kJ/kg) - (5kg)(3000kJ/kg) = -2500 kJ
 
Yes, you would.

<br /> \Delta E = m(e_2 - e_1).<br />

By the way, the solution in the first post (after the correction) will give you the work done by the piston on the steam. But if I see it right the question is about the opposite value.
 
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