Thevenin Equivalent Finding Isc

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Discussion Overview

The discussion revolves around finding the short-circuit current (Isc) in a circuit analysis problem related to Thevenin's theorem. Participants explore the implications of applying a short circuit across specific components and how it affects voltage and resistance in the circuit.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses confusion about why the 10 ohm resistor is bypassed when a short circuit is applied, referencing a solution that indicates this behavior.
  • Another participant questions what happens to the voltage across the 10 ohm resistor when the short is applied.
  • There is a repeated inquiry about whether the voltage across the 10 ohm resistor goes to zero and the reasoning behind this outcome.
  • A participant suggests that understanding Ohm's Law and the concept of combining resistances in parallel is necessary to clarify the situation.
  • It is noted that the short circuit acts as a zero ohm resistance in parallel with the 10 ohm resistor, prompting a discussion about the net resistance and the implications for voltage drop when current flows through the circuit.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there are multiple questions and uncertainties regarding the behavior of the circuit components when the short circuit is applied.

Contextual Notes

The discussion highlights the need for a deeper understanding of circuit theory, particularly in relation to Ohm's Law and parallel resistance calculations. There are unresolved questions about the voltage behavior and the implications of the short circuit on the circuit's overall characteristics.

jdawg
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Warning: Missing problem statement

Homework Statement

Homework Equations

The Attempt at a Solution


So far I've found Vout, but I'm a little confused about finding ISC. The solution to my homework says that in Figure 2 the 10 ohm resistor gets by passed due to the short across the open voltage. Why does this happen? Thanks!
 

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When the short is applied what happens to the voltage across the 10R?
 
Does it go to zero? Why does that happen?
 
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jdawg said:
Does it go to zero? Why does that happen?
I think you need to do a little investigation of Ohm's Law and combining resistances in parallel.

The short circuit is a zero Ohm resistance placed across the terminals. In this case it places the equivalent of a zero Ohm resistor in parallel with the 10 Ohm resistance. What's the net resistance of 10 Ohms in parallel with zero Ohms?

What does Ohm's Law say about the potential drop across that net resistance when some current ##I## flows through it?
 
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