Thevenin's Problem: Solve for Voltage, Current, Power

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The discussion focuses on solving Thevenin's problem by determining voltage, current, and power in a circuit with a load resistance. The initial calculations involve removing the load resistor (RL) and finding the voltage at a junction between two resistors, resulting in 9V. The source impedance is calculated using the formula for resistors in parallel. Participants are encouraged to continue the analysis by calculating the voltage and source impedance at a specific point in the circuit. The conversation emphasizes the importance of these calculations for understanding Thevenin's theorem.
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Homework Statement



vuZohAF.png

Homework Equations


V=IR
P=I^2R
maximum power when load resistance = thevenin's resistance

The Attempt at a Solution


I have been able to work out the new load resistance but none of the other values correctly.
 
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1. Remove RL. Now the voltage at the junction between 20Ω and 30Ω is \frac{30\Omega}{(20+30)\Omega}\cdot 15V = 9V with a source impedance of 20\Omega \left\lvert \right\rvert 30\Omega =\frac{20\cdot 30}{20 + 30}\Omega...
 
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Svein said:
1. Remove RL. Now the voltage at the junction between 20Ω and 30Ω is \frac{30\Omega}{(20+30)\Omega}\cdot 15V = 9V with a source impedance of 20\Omega \left\lvert \right\rvert 30\Omega =\frac{20\cdot 30}{20 + 30}\Omega...

Thank you for your reply, also how do you calculate the other values
 
merchant said:
Thank you for your reply, also how do you calculate the other values
I have given you the first steps. Now try the next: With RL still disconnected, find the voltage and the source impedance at point A.
 

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