This function fails the conservative test, yet it is path independent?

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SUMMARY

The discussion centers on evaluating the line integral \(\int_C \tan(y) \, dx + x \sec^2(y) \, dy\) and determining its path independence. The integrand components are defined as \(M = \tan(y)\) and \(N = x \sec^2(y)\). To verify if the force is conservative, the condition \(\frac{\partial M}{\partial y} = \frac{\partial N}{\partial x}\) must be satisfied. The partial derivatives indicate that the force is not conservative due to the inequality established between the derivatives.

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flyingpig
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Homework Statement



Show that the line integral is path independent and evaluate the integral

\int_C tan(y) dx + x sec^2 (y) dy

The Attempt at a Solution



\frac{\partial }{\partial x}(tan(y)) = 0 \neq 2xsec^2(y)tan(y) = x\frac{\partial }{\partial y}(sec^2(y))
 
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I believe your problem is stemming from the presence of the differentials, dx and dy. The general form of a line integral is the following:
<br /> \int_C M dx + N dy<br />

Where M & N relate to the quantities in your problem such that:

M = tan(y)
N = x sec^2 (y)

Now we know for a force to be conservative it must satisfy the following relationship:

\frac{\partial M }{\partial y} = \frac{\partial N }{\partial x}

Given this information, is your force conservative?

Hope this helps.

Joe
 

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