Three masses suspended by cables: Force Question: HELP PLEASE

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The discussion focuses on calculating the tension in cables supporting three different masses. The weights of the masses are calculated using the formula W = mg, resulting in tensions of 147 N for the 15 kg mass, 107.8 N for the 11 kg mass, and 49 N for the 5 kg mass. The original poster expresses confidence in their calculations but seeks confirmation due to time constraints before the homework deadline. Other participants confirm that the calculations are correct. The thread highlights the importance of understanding tension in physics problems involving suspended masses.
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Homework Statement



Three masses are suspended by cables as shown. Find the tension in each cable.

Picture:

2drz8gm.jpg


Homework Equations



W=mg

The Attempt at a Solution



T1: W= mg
= 15 kg x (9.8 m/s^2)
= 147 N

T2: W= mg
= 11kg x (9.8m/s^2)
= 107.8 N

T3: W=mg
=5kg x (9.8m/s^2)
= 49 N


Is this right? I'm pretty confident in it, but the lecture I watched before attempting this among several other problems wasn't very helpful. Thank you!
 
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Bump? This homework is due in less than 2 hours and I'm stressing that I'm going to get it wrong.
 
Yes, that looks correct.
 
Thank you.
 
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