Threshold, proton-proton-collision

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SUMMARY

The discussion centers on calculating the threshold energy for the reaction involving proton-proton collisions resulting in a K+ meson. The reaction is represented as p + p → p + p + K+. It is established that to produce a K+, one proton must be replaced by a Λ(1116) hyperon due to strangeness conservation, which necessitates the involvement of weak interactions. The conservation of baryon number and electric charge is also emphasized, indicating that the proposed reaction does not conserve electric charge.

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Abigale
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Hello,

I regard a proton-proton collision. (Target at rest.)
Here accrues a <br /> K^{+}(494)<br />-meson.

I want to callculate the threshold energy.

But I think for callculating the threshold I have to know all participant of the product.
Can i assume, that the protons will not be destroyed?

$$
p~+p~\rightarrow~p~+~p~+~K^{+}
$$

(On the other hand I know, that for producing a K^{+}, which contains an \bar{s}-quark, due to strangeness-conservation, a proton must be replaced by an \lambda(1116)-hyperon, which contains an s-quark. )

THX
Abby
 
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Baryon number is conserved, and the proton is the lightest baryon. With two protons in the final state (instead of hyperons), the process requires the weak interaction, it should be much more frequent with enough energy to do s sbar production.
 
Sorry, but the Kaon reaction you write doesn't conserve electric charge
 

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