Throwing everything I can at this one

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Homework Help Overview

The discussion revolves around the integration of functions involving inverse trigonometric functions, specifically arcsin and arctan, within the context of definite integrals. Participants are exploring various methods to approach the integral expressions provided.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss attempts at integration by parts and u-substitution, expressing uncertainty about the effectiveness of these methods. Questions arise regarding the correct interpretation of the integral and the relationship between the functions involved.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on potential methods and expressing frustration over the complexity of the problem. Some guidance has been offered regarding the use of substitution, particularly in relation to the derivative of arcsin.

Contextual Notes

Participants mention the challenges of learning new integration techniques in a short time frame, highlighting the need for a deeper understanding of derivatives related to inverse trigonometric functions.

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Homework Statement





\int \frac{(arcsinx)^{2}}{\sqrt{1-x^{2}}} dx




Homework Equations





The Attempt at a Solution



First I attempted by parts, that got nowhere. Then, I attempted a u substitution for u = arcsin x, and when that did nothing I attempted one for u = arcsinx^2.

I have no idea what to do with this one. How should I approach the problem?
 
Last edited:
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1MileCrash said:

Homework Statement





\int \frac{(arctanx)^{2}}{\sqrt{1-x^{2}}} dx




Homework Equations





The Attempt at a Solution



First I attempted by parts, that got nowhere. Then, I attempted a u substitution for u = arcsin x, and when that did nothing I attempted one for u = arcsinx^2.

I have no idea what to do with this one. How should I approach the problem?

Is the problem \int \frac{(arctanx)^{2}}{\sqrt{1-x^{2}}} dx or \int \frac{(arcsinx)^{2}}{\sqrt{1-x^{2}}} dx?
 
arcsin, definitely. Sorry about that.
 
Your original intuition looks fine. Set u = arcsinx. du = ...?
 
My original intuition of integration by parts?? I didn't think that was the preferred method because I'd have to integrate (1-x^2)^(-1/2) which would just complicate it
 
Ok wow, this is an extremely simple substitution problem, provided you actually remember the derivative has a square root in the denominator.

Try doing it thinking it's like the arctan derivative and you will see my frustration.
 
1MileCrash said:
Try doing it thinking it's like the arctan derivative and you will see my frustration.

If it was, I have no idea how to solve that. You probably won't make that mistake again.
 
gb7nash said:
If it was, I have no idea how to solve that. You probably won't make that mistake again.

Numerically. :wink:
 
Ignea_unda said:
Numerically. :wink:
Not really a solution for an indefinite integral...
 
  • #10
Mark44 said:
Not really a solution for an indefinite integral...

Touche, I guess...didn't look that closely and missed the lack of limits.
 
  • #11
Integration is getting really difficult for me with all the new techniques I had to learn in like 2 days.

How do you guys decide which method to try first?
 
  • #12
Usually depending on how difficult it looks, you should try to do substitution before you attempt integration by parts.

For example, in your question, you can see a relation between arcsin(x) and 1/sqrt(1-x^2), substitution might work here.
 
  • #13
I have another question.

One of my favorite integrals to solve is actually integral of the arctangent. I like it because it's kind of neat, integrate by parts once, then u-substitution once, it looks good on paper.

However, you need to know it's derivative when you call it u for integration by parts.

I just have it memorized. I don't really intuitively understand how one arrives at the derivative of arctangent. Is it just something that is observable or can it actually be shown?
 

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